Russian clubs learned their opponents in the 1/16 finals of the Europa League. Petersburg «Zenith» will play against Belgian Anderlecht, FC «Rostov» will hold the matches against Sparta and FC «Krasnodar» will try to beat the Turkish «Fenerbahce».
In Nyon, Switzerland hosted the draw for the pairs of 1/16 finals of Europa League football. Their opponents at this stage, learned three of the Russian club, reports TASS.
In particular, it was found out that Petersburg «Zenith» will play against Belgian «Anderlecht». The team from Brussels had already played with another Russian club this season. In the third qualifying round of the Champions League she met with «Rostov» and lost him both games (2:2; 0:2), out in a tournament of a lower rank. Once in the group, the Belgians were the leaders for a long time, but then lost at home to the French «Saint-Etienne», and ranked only second place in the Quartet, which also spoke German «Mainz» and the Azerbaijani «Gabala».
In turn, his opponent at the 1/16 finals learned and «Rostov». It fell to him to play with Sparta, which a year ago at this same stage, knocked out of FC «Krasnodar». This year, praguers lost Romanian «Steaua» in the qualifying round of the Champions League, losing on the sum of meetings (1:1; 0:2). However their group in the Europa League team won. It was stronger than the Israeli «Hapoel», English «Southampton» and Milan «inter».
Also his rival learned of FC «Krasnodar». This team had to play with the Turkish «Fenerbahce», which last season knocked out Lokomotiv Moscow at the same stage. This command also tried to get into the Champions League, but it stopped the «Monaco» (2:1; 1:3). In the Europa League, the Turkish club has performed very well, taking first place in group A, which was also the English «Manchester United», the Dutch «Feyenoord» and Lugansk «dawn».